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60x^2-37x-6=0
a = 60; b = -37; c = -6;
Δ = b2-4ac
Δ = -372-4·60·(-6)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-53}{2*60}=\frac{-16}{120} =-2/15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+53}{2*60}=\frac{90}{120} =3/4 $
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